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(|7x+4|)/(8)=3

7x+48=3 \frac{|7 x+4|}{8}=3

Full solution

Q. 7x+48=3 \frac{|7 x+4|}{8}=3
  1. Isolate absolute value: First, let's isolate the absolute value by multiplying both sides by 88.\newline7x+48×8=3×8\frac{|7x+4|}{8} \times 8 = 3 \times 8\newline7x+4=24|7x+4| = 24
  2. Consider two cases: Now we need to consider the two cases for the absolute value.\newlineCase 11: 7x+4=247x + 4 = 24\newlineCase 22: 7x+4=247x + 4 = -24
  3. Solve Case 11: Let's solve Case 11.\newline7x+4=247x + 4 = 24\newlineSubtract 44 from both sides.\newline7x=207x = 20\newlineDivide by 77.\newlinex=207x = \frac{20}{7}
  4. Solve Case 22: Now, let's solve Case 22.\newline7x+4=247x + 4 = -24\newlineSubtract 44 from both sides.\newline7x=287x = -28\newlineDivide by 77.\newlinex=28/7x = -28/7\newlinex=4x = -4

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