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Let’s check out your problem:

(6÷3+5)×(11-4)=

(6÷3+5)×(11−4)= (6 \div 3+5) \times(11-4)=

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Full solution

Q. (6÷3+5)×(11−4)= (6 \div 3+5) \times(11-4)=
  1. Calculate Division and Subtraction: First, let's do the division and subtraction inside the parentheses.\newlineCalculate 6÷36\div3 and 11−411-4.\newline6÷3=26\div3 = 2 and 11−4=711-4 = 7.
  2. Add Result to 55: Now, add the result of the division to 55. 2+5=72 + 5 = 7.
  3. Multiply Results: Finally, multiply the results of the two parentheses. 7×7=497 \times 7 = 49.

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