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(-6)^(3)÷3^(2)÷[-9-(-8)]^(3)

(6)3÷32÷[9(8)]3 (-6)^{3} \div 3^{2} \div[-9-(-8)]^{3}

Full solution

Q. (6)3÷32÷[9(8)]3 (-6)^{3} \div 3^{2} \div[-9-(-8)]^{3}
  1. Calculate Exponents: Calculate the value of (6)3(-6)^{3}.\newline(6)3=6×6×6=216(-6)^{3} = -6 \times -6 \times -6 = -216
  2. Calculate Power: Calculate the value of 323^{2}. \newline32=3×3=93^{2} = 3 \times 3 = 9
  3. Calculate Brackets: Calculate the value inside the brackets [9(8)][-9-(-8)].\newline[\(-9-(8-8)] = 9-9 + 88 = 1-1
  4. Calculate Cubes: Calculate the value of [9(8)]3[-9-(-8)]^{3}.$(1)3=1×1×1=1\$(-1)^{3} = -1 \times -1 \times -1 = -1
  5. Divide Exponents: Divide the result of (6)3(-6)^{3} by 323^{2}.\newline216÷9=24-216 \div 9 = -24
  6. Final Division: Divide the result of the previous step by [9(8)]3[-9-(-8)]^{3}. 24÷1=24-24 \div -1 = 24

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