{:[-5y=-5],[7x+6y=7]:} Is (5,1) a solution of the system? Choose 1 answer: (A) Yes (B) No

Substitute and check first equation: First, we will substitute the point (5,1) into the first equation and check if it holds true. The first equation is -5y = -5. If we substitute y=1, we get -5*1 = -5. Verify first equation result: After performing the calculation, we find that -5 = -5, which is true. Therefore, the point (5,1) satisfies the first equation. Substitute and check second equation: Next, we will substitute the point (5,1) into the second equation and check if it holds true. The second equation is 7x + 6y = 7. If we substitute x=5 and y=1, we get 7*5 + 6*1 = 7. Verify second equation result: After performing the calculation, we find that 35 + 6 = 41, which is not equal to 7. Therefore, the point (5,1) does not satisfy the second equation. Point does not satisfy both equations: Since the point (5,1) does not satisfy both equations, it is not a solution to the system of equations.

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{:[-5y=-5],[7x+6y=7]:}
Is
(5,1) a solution of the system?
Choose 1 answer:
(A) Yes
(B)
No

$\begin{array}{c} -5 y=-5 \\ 7 x+6 y=7 \end{array}$ $\newline$ Is $(5,1)$ a solution of the system? $\newline$ Choose $1$ answer: $\newline$ (A) Yes $\newline$ (B) No

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Algebra 2

Is (x, y) a solution to the system of equations?

Full solution

\begin{array}{c} -5 y=-5 \\ 7 x+6 y=7 \end{array}

\newline

(5,1)

a solution of the system?

\newline

Choose

1

answer:

\newline

(A) Yes

\newline

(B) No

Substitute and check first equation: First, we will substitute the point $(5,1)$ into the first equation and check if it holds true. The first equation is $-5y = -5$ . If we substitute $y=1$ , we get $-5 \times 1 = -5$ .
Verify first equation result: After performing the calculation, we find that $-5 = -5$ , which is true. Therefore, the point $(5,1)$ satisfies the first equation.
Substitute and check second equation: Next, we will substitute the point $(5,1)$ into the second equation and check if it holds true. The second equation is $7x + 6y = 7$ . If we substitute $x=5$ and $y=1$ , we get $7 \cdot 5 + 6 \cdot 1 = 7$ .
Verify second equation result: After performing the calculation, we find that $35 + 6 = 41$ , which is not equal to $7$ . Therefore, the point $(5,1)$ does not satisfy the second equation.
Point does not satisfy both equations: Since the point $(5,1)$ does not satisfy both equations, it is not a solution to the system of equations.