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-5i*(5i-5)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$-5 i \cdot(5 i-5)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

-5 i \cdot(5 i-5)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Distribute $-5i$ : Distribute $-5i$ to both terms inside the parentheses $(5i-5)$ . $\newline$ $-5i \times 5i = -25i^2$ $\newline$ $-5i \times -5 = +25i$
Replace $i^2$ with $-1$ : Remember that $i^2 = -1$ . Replace $i^2$ with $-1$ in the expression $-25i^2$ . $\newline$ $-25 \times (-1) = 25$
Combine the results: Combine the results from Step $1$ and Step $2$ . $25$ (from $-25i^2$ ) + $25i$ (from $+25i$ )
Write the final answer: Write the final answer in the form $a+bi$ . The real part $a$ is $25$ , and the imaginary part $b$ is $25$ .

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