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(4xy)^(2)

$(4 x y)^{2}$

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Powers with negative bases

Full solution

Q.

(4 x y)^{2}

Apply Power Rule: Apply the power rule to the expression $(4xy)^2$ . According to the power rule, $(ab)^n = a^n \times b^n$ , where $a$ and $b$ are the base terms and $n$ is the exponent. In this case, $a = 4x$ , $b = y$ , and $n = 2$ . $(4xy)^2 = (4x)^2 \times y^2$
Calculate $4x$ Square: Calculate the square of $4x$ .
$(4x)^2 = 4^2 \times x^2$
$4^2 = 16$ , so we have:
$(4x)^2 = 16 \times x^2$
Calculate $y$ Square: Calculate the square of $y$ . $\newline$ $y^2$ is already in its simplest form, as it represents $y$ multiplied by itself. $\newline$ $y^2 = y \times y$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ $(4xy)^2 = (16 \times x^2) \times y^2$
Write Final Expression: Write the final expression. $\newline$ The final expression is the product of $16$ , $x^2$ , and $y^2$ . $\newline$ $(4xy)^2 = 16x^2y^2$

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