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{:[4x-3y=12],[-x+3y=6]:}

66.\newline4x3y=12x+3y=6 \begin{array}{l} 4 x-3 y=12 \\ -x+3 y=6 \end{array}

Full solution

Q. 66.\newline4x3y=12x+3y=6 \begin{array}{l} 4 x-3 y=12 \\ -x+3 y=6 \end{array}
  1. Combine equations: Let's add the two equations together to eliminate yy.4x3y+(x+3y)=12+64x - 3y + (-x + 3y) = 12 + 63x=183x = 18
  2. Solve for x: Now, divide both sides by 33 to solve for x.3x3=183\frac{3x}{3} = \frac{18}{3}x=6x = 6
  3. Substitute xx into second equation: Substitute x=6x = 6 into the second equation to find yy.\newline6+3y=6-6 + 3y = 6\newline3y=123y = 12
  4. Solve for y: Divide both sides by 33 to solve for y.\newline3y3=123\frac{3y}{3} = \frac{12}{3}\newliney=4y = 4

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