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Let’s check out your problem:
∴
4
x
3
−
6
x
2
−
20
=
1
\therefore 4 x^{3}-6 x^{2}-20=1
∴
4
x
3
−
6
x
2
−
20
=
1
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Math Problems
Algebra 2
Add, subtract, multiply, and divide polynomials
Full solution
Q.
∴
4
x
3
−
6
x
2
−
20
=
1
\therefore 4 x^{3}-6 x^{2}-20=1
∴
4
x
3
−
6
x
2
−
20
=
1
Rewrite equation to set zero:
Rewrite the equation to set it to zero.
\newline
0.4
x
3
−
6
x
2
−
20
−
1
=
0
0.4x^3 - 6x^2 - 20 - 1 = 0
0.4
x
3
−
6
x
2
−
20
−
1
=
0
\newline
0.4
x
3
−
6
x
2
−
21
=
0
0.4x^3 - 6x^2 - 21 = 0
0.4
x
3
−
6
x
2
−
21
=
0
Multiply to clear decimal:
Multiply through by
10
10
10
to clear the decimal.
\newline
10
(
0.4
x
3
)
−
10
(
6
x
2
)
−
10
(
21
)
=
10
(
0
)
10(0.4x^3) - 10(6x^2) - 10(21) = 10(0)
10
(
0.4
x
3
)
−
10
(
6
x
2
)
−
10
(
21
)
=
10
(
0
)
\newline
4
x
3
−
60
x
2
−
210
=
0
4x^3 - 60x^2 - 210 = 0
4
x
3
−
60
x
2
−
210
=
0
Factor out greatest common factor:
Factor out the greatest common factor, which is
2
2
2
.
2
(
2
x
3
−
30
x
2
−
105
)
=
0
2(2x^3 - 30x^2 - 105) = 0
2
(
2
x
3
−
30
x
2
−
105
)
=
0
Solve factored equation:
Solve the factored equation.
\newline
2
x
3
−
30
x
2
−
105
=
0
2x^3 - 30x^2 - 105 = 0
2
x
3
−
30
x
2
−
105
=
0
\newline
Divide by
2
2
2
:
\newline
x
3
−
15
x
2
−
52.5
=
0
x^3 - 15x^2 - 52.5 = 0
x
3
−
15
x
2
−
52.5
=
0
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