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(4x^(3)-23 x-21)÷(2x+3)

88. (4x323x21)÷(2x+3) \left(4 x^{3}-23 x-21\right) \div(2 x+3)

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Q. 88. (4x323x21)÷(2x+3) \left(4 x^{3}-23 x-21\right) \div(2 x+3)
  1. Set up polynomial long division: Step 11: Set up the polynomial long division.\newlineDivide 4x34x^3 by 2x2x to get 2x22x^2.\newlineSubtract (2x2(2x+3))(2x^2 \cdot (2x + 3)) from (4x323x21)(4x^3 - 23x - 21).
  2. Simplify the subtraction: Step 22: Simplify the subtraction.\newline(4x323x21)(4x3+6x2)=6x223x21(4x^3 - 23x - 21) - (4x^3 + 6x^2) = -6x^2 - 23x - 21.
  3. Continue the division: Step 33: Continue the division.\newlineDivide 6x2-6x^2 by 2x2x to get 3x-3x.\newlineSubtract (3x(2x+3))(-3x * (2x + 3)) from (6x223x21)(-6x^2 - 23x - 21).
  4. Simplify the subtraction: Step 44: Simplify the subtraction.\newline(6x223x21)(6x29x)=14x21(-6x^2 - 23x - 21) - (-6x^2 - 9x) = -14x - 21.
  5. Continue the division: Step 55: Continue the division.\newlineDivide 14x-14x by 2x2x to get 7-7.\newlineSubtract (7(2x+3))(-7 * (2x + 3)) from (14x21)(-14x - 21).
  6. Simplify the subtraction: Step 66: Simplify the subtraction.\newline(14x21)(14x21)=0(-14x - 21) - (-14x - 21) = 0.

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