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(4x+3)^(2)=24

(4x+3)2=24 (4 x+3)^{2}=24

Full solution

Q. (4x+3)2=24 (4 x+3)^{2}=24
  1. Write Equation: First, let's write down the equation we need to solve.\newline(4x+3)2=24(4x+3)^{2}=24
  2. Take Square Root: Now, we need to get rid of the square by taking the square root of both sides.\newline(4x+3)2=24\sqrt{(4x+3)^{2}} = \sqrt{24}
  3. Simplify Square Root: After taking the square root, we have: 4x+3=±244x+3 = \pm\sqrt{24}
  4. Subtract 33: Let's simplify 24\sqrt{24} to make it easier.\newline24=(46)=46=26\sqrt{24} = \sqrt{(4\cdot6)} = \sqrt{4} \cdot \sqrt{6} = 2\sqrt{6}\newlineSo, 4x+3=±264x+3 = \pm2\sqrt{6}
  5. Divide by 44: Now, we'll solve for xx by subtracting 33 from both sides.4x=±2634x = \pm 2\sqrt{6} - 3
  6. Divide by 44: Now, we'll solve for xx by subtracting 33 from both sides.4x=±2634x = \pm 2\sqrt{6} - 3Next, we divide both sides by 44 to isolate xx.x=±2634x = \frac{\pm 2\sqrt{6} - 3}{4}