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(4r2−3r+2)−(−r2−3r)=(4r^2-3r+2) -(-r^2-3r)=

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Full solution

Q. (4r2−3r+2)−(−r2−3r)=(4r^2-3r+2) -(-r^2-3r)=
  1. Distribute Negative Sign: Distribute the negative sign to the terms inside the parentheses.\newlineTo subtract the polynomial −(−r2−3r)-(-r^2-3r), we need to distribute the negative sign to each term inside the parentheses, which changes the signs of the terms.\newlineSo, −(−r2)-(-r^2) becomes +r2+r^2 and −(−3r)-(-3r) becomes +3r+3r.
  2. Combine Like Terms: Combine like terms.\newlineNow we combine the like terms from the expression (4r2−3r+2)+(r2+3r)(4r^2-3r+2) + (r^2+3r).\newline4r2+r2=5r24r^2 + r^2 = 5r^2 (combining like terms for r2r^2)\newline−3r+3r=0-3r + 3r = 0 (combining like terms for rr)\newlineThe constant term remains as +2+2.
  3. Write Final Expression: Write the final simplified expression.\newlineSince −3r-3r and +3r+3r cancel each other out, we are left with:\newline5r2+25r^2 + 2\newlineThis is the simplified form of the given expression.

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