Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

(40 points)
Let 
F(x)=int_(0)^(x)sin(t^(3))dt for 
0 <= x <= 2.
On what intervals if 
F(x) increasing?

(4040 points)\newlineLet F(x)=0xsin(t3)dt F(x)=\int_{0}^{x} \sin \left(t^{3}\right) d t for 0x2 0 \leq x \leq 2 .\newlineOn what intervals if F(x) F(x) increasing?

Full solution

Q. (4040 points)\newlineLet F(x)=0xsin(t3)dt F(x)=\int_{0}^{x} \sin \left(t^{3}\right) d t for 0x2 0 \leq x \leq 2 .\newlineOn what intervals if F(x) F(x) increasing?
  1. Define F(x)F'(x): To find where F(x)F(x) is increasing, we need to look at the derivative F(x)F'(x) because if F(x)>0F'(x) > 0, then F(x)F(x) is increasing.
  2. Calculate F(x)F'(x): By the Fundamental Theorem of Calculus, F(x)=sin(x3)F'(x) = \sin(x^3).
  3. Find intervals for sin(x3)\sin(x^3): We need to find the intervals where sin(x3)>0\sin(x^3) > 0.
  4. Determine positive intervals: Since sin(x)\sin(x) is positive in the first and second quadrants, sin(x3)\sin(x^3) will be positive when x3x^3 is in the first and second quadrants.
  5. Identify first and second quadrants: The first quadrant for x3x^3 is from 00 to (π/2)1/3(\sqrt{\pi}/2)^{1/3} and the second quadrant is from (π/2)1/3(\sqrt{\pi}/2)^{1/3} to (3π/2)1/3(\sqrt{3\pi}/2)^{1/3}.

More problems from Intermediate Value Theorem