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$(4^{0} + 4^{-1}) \times 2^{2}$

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Powers with negative bases

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Q.

(4^{0} + 4^{-1}) \times 2^{2}

Calculate $4^0$ : Calculate $4$ to the power $0$ . $\newline$ $4^0 = 1$
Calculate $4^{-1}$ : Calculate $4$ to the power $-1$ . $\newline$ $4^{-1} = \frac{1}{4}$
Add results: Add the results from step $1$ and step $2$ . $\newline$ $1 + \frac{1}{4} = 1.25$
Calculate $2^2$ : Calculate $2$ to the power $2$ . $\newline$ $2^2 = 4$
Multiply results: Multiply the result from step $3$ by the result from step $4$ . $\newline$ $1.25 \times 4 = 5$

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