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\(4^{1111})(44^{−8-8})\

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Full solution

Q. \(4^{1111})(44^{−8-8})\
  1. Apply law of exponents: Apply the law of exponents for multiplication, which states that when multiplying like bases, you add the exponents.\newlineSo, (411)(4−8)(4^{11})(4^{-8}) becomes 411+(−8)4^{11 + (-8)}.
  2. Perform exponent addition: Perform the addition of the exponents. 11+(−8)11 + (-8) equals 33. So, 411+(−8)4^{11 + (-8)} becomes 434^3.
  3. Calculate final value: Calculate the value of 434^3. 434^3 equals 4×4×44 \times 4 \times 4, which is 6464.

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