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{:[(3y)/(2)-7=2],[y=?]:}

3y27=2y=? \begin{array}{l}\frac{3 y}{2}-7=2 \\ y=?\end{array}

Full solution

Q. 3y27=2y=? \begin{array}{l}\frac{3 y}{2}-7=2 \\ y=?\end{array}
  1. Isolate y term: First, let's isolate the term with yy by adding 77 to both sides of the equation.\newline3y27+7=2+7\frac{3y}{2} - 7 + 7 = 2 + 7\newline3y2=9\frac{3y}{2} = 9
  2. Multiply by 22: Now, multiply both sides by 22 to get rid of the fraction.\newline2×3y2=9×22 \times \frac{3y}{2} = 9 \times 2\newline3y=183y = 18
  3. Divide by 33: Finally, divide both sides by 33 to solve for y.\newline3y3=183\frac{3y}{3} = \frac{18}{3}\newliney=6y = 6

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