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(3x-9)^(2)=2x+2(2x+29)

(3x−9)2=2x+2(2x+29) (3 x-9)^{2}=2 x+2(2 x+29)

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Full solution

Q. (3x−9)2=2x+2(2x+29) (3 x-9)^{2}=2 x+2(2 x+29)
  1. Expand left side: Expand the left side using the formula (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2.(3x−9)2=(3x)2−2⋅(3x)⋅9+(9)2(3x-9)^2 = (3x)^2 - 2\cdot(3x)\cdot9 + (9)^2=9x2−54x+81= 9x^2 - 54x + 81
  2. Distribute on right side: Distribute the 22 on the right side of the equation.2x+2(2x+29)=2x+4x+582x + 2(2x+29) = 2x + 4x + 58=6x+58= 6x + 58
  3. Set equation to zero: Set the equation equal to zero by subtracting the right side from the left side.\newline9x2−54x+81−(6x+58)=09x^2 - 54x + 81 - (6x + 58) = 0
  4. Combine like terms: Combine like terms.\newline9x2−54x+81−6x−58=09x^2 - 54x + 81 - 6x - 58 = 0\newline9x2−60x+23=09x^2 - 60x + 23 = 0

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