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{:[-3x-8y=-8],[y=2-x]:} Is (0,1) a solution of the system? Choose 1 answer: (A) Yes (B) No

−3x−8y=−8 -3 x-8 y=-8 \newliney=2−x y=2-x \newlineIs (0,1) (0,1) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

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Full solution

Q. −3x−8y=−8 -3 x-8 y=-8 \newliney=2−x y=2-x \newlineIs (0,1) (0,1) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and check first equation: First, we will substitute the point (0,1)(0,1) into the first equation and check if it holds true. The first equation is −3x−8y=−8-3x - 8y = -8. If we substitute x=0x=0 and y=1y=1, we get −3⋅0−8⋅1=−8-3\cdot 0 - 8\cdot 1 = -8.
  2. Check if point satisfies first equation: After performing the calculation, we find that 0−8=−80 - 8 = -8, which is true. Therefore, the point (0,1)(0,1) satisfies the first equation.
  3. Substitute and check second equation: Next, we will substitute the point (0,1)(0,1) into the second equation and check if it holds true. The second equation is y=2−xy = 2 - x. If we substitute x=0x=0 and y=1y=1, we get 1=2−01 = 2 - 0.
  4. Check if point satisfies second equation: After performing the calculation, we find that 1=21 = 2, which is not true. Therefore, the point (0,1)(0,1) does not satisfy the second equation.
  5. Point does not satisfy both equations: Since the point (0,1)(0,1) does not satisfy both equations, it is not a solution to the system of equations.

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