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{:[3x-4y=-5],[y=4x-2]:}
Is 
(1,2) a solution of the system?
Choose 1 answer:
(A) Yes
(B) 
No

3x4y=5 3 x-4 y=-5 \newliney=4x2 y=4 x-2 \newlineIs (1,2) (1,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. 3x4y=5 3 x-4 y=-5 \newliney=4x2 y=4 x-2 \newlineIs (1,2) (1,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and check first equation: First, we will substitute the point (1,2)(1,2) into the first equation and check if it holds true. The first equation is 3x4y=53x - 4y = -5. If we substitute x=1x=1 and y=2y=2, we get 3142=53 \cdot 1 - 4 \cdot 2 = -5.
  2. Verify first equation holds true: After performing the calculation, we find that 38=53 - 8 = -5, which is true. Therefore, the point (1,2)(1,2) satisfies the first equation.
  3. Substitute and check second equation: Next, we will substitute the point (1,2)(1,2) into the second equation and check if it holds true. The second equation is y=4x2y = 4x - 2. If we substitute x=1x=1 and y=2y=2, we get 2=4122 = 4 \cdot 1 - 2.
  4. Verify second equation holds true: After performing the calculation, we find that 2=422 = 4 - 2, which is also true. Therefore, the point (1,2)(1,2) satisfies the second equation as well.
  5. Solution to the system of equations: Since the point (1,2)(1,2) satisfies both equations, it is a solution to the system of equations.

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