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{:[3x+3y=42],[x-3y=33]:}

$\begin{array}{r}3 x+3 y=42 \\ x-3 y=33\end{array}$

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Write an equation word problem

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Q.

\begin{array}{r}3 x+3 y=42 \\ x-3 y=33\end{array}

Combine equations: Let's add the two equations together to eliminate $y$ . $(3x + 3y) + (x - 3y) = 42 + 33$ $4x = 75$ Now, divide both sides by $4$ to find $x$ . $x = \frac{75}{4}$ $x = 18.75$
Find x: Now, let's substitute $x$ back into one of the original equations to find $y$ . Using the second equation: $x - 3y = 33$ $18.75 - 3y = 33$ Subtract $18.75$ from both sides. $-3y = 33 - 18.75$ $-3y = 14.25$ Now, divide both sides by $-3$ to find $y$ . $y = \frac{14.25}{-3}$ $y$ $0$

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