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(3v+2)-((2)/(3)v-(1)/(4))
Which of the following is equivalent to the given expression?
Choose 1 answer:
(A) 
(7)/(3)v+(7)/(4)
(B) 
(7)/(3)v+(9)/(4)
(C) 
2v^(2)+(1)/(2)
(D) 
2v^(2)+(7)/(12)v-(1)/(2)

(3v+2)(23v14) (3 v+2)-\left(\frac{2}{3} v-\frac{1}{4}\right) \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) 73v+74 \frac{7}{3} v+\frac{7}{4} \newline(B) 73v+94 \frac{7}{3} v+\frac{9}{4} \newline(C) 2v2+12 2 v^{2}+\frac{1}{2} \newline(D) 2v2+712v12 2 v^{2}+\frac{7}{12} v-\frac{1}{2}

Full solution

Q. (3v+2)(23v14) (3 v+2)-\left(\frac{2}{3} v-\frac{1}{4}\right) \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) 73v+74 \frac{7}{3} v+\frac{7}{4} \newline(B) 73v+94 \frac{7}{3} v+\frac{9}{4} \newline(C) 2v2+12 2 v^{2}+\frac{1}{2} \newline(D) 2v2+712v12 2 v^{2}+\frac{7}{12} v-\frac{1}{2}
  1. Simplify Expression: First, let's simplify the expression (3v+2)(23v14)(3v+2)-\left(\frac{2}{3}v-\frac{1}{4}\right). We'll start by distributing the negative sign to the terms inside the second set of parentheses.\newline(3v+2)(23v14)=3v+223v+14(3v+2)-\left(\frac{2}{3}v-\frac{1}{4}\right) = 3v + 2 - \frac{2}{3}v + \frac{1}{4}
  2. Combine Like Terms: Now, we combine like terms. The vv terms are 3v3v and (23)v-\left(\frac{2}{3}\right)v, and the constant terms are 22 and 14\frac{1}{4}.\newlineTo combine the vv terms: 3v(23)v=(93)v(23)v=(73)v3v - \left(\frac{2}{3}\right)v = \left(\frac{9}{3}\right)v - \left(\frac{2}{3}\right)v = \left(\frac{7}{3}\right)v\newlineTo combine the constant terms: \(2 + \frac{11}{44} = \left(\frac{88}{44}\right) + \left(\frac{11}{44}\right) = \left(\frac{99}{44}\right)
  3. Final Simplified Expression: So, the simplified expression is (73)v+(94)(\frac{7}{3})v + (\frac{9}{4}). This matches answer choice (B).

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