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{:[3a+5u=17],[2a+u=9]:}

{:\begin{align*}[33a+55u&=1717],[22a+u&=99]:\end{align*}

Full solution

Q. {:\begin{align*}[33a+55u&=1717],[22a+u&=99]:\end{align*}
  1. Solve for 'u': Step 11: Solve the second equation for 'u'.\newlineGiven: 2a+u=92a + u = 9\newlineSubtract 2a2a from both sides: u=92au = 9 - 2a
  2. Substitute into first equation: Step 22: Substitute the expression for uu from Step 11 into the first equation.\newlineSubstitute u=92au = 9 - 2a into 3a+5u=173a + 5u = 17:\newline3a+5(92a)=173a + 5(9 - 2a) = 17
  3. Simplify and solve for 'a': Step 33: Simplify and solve for 'a'.\newline3a+4510a=173a + 45 - 10a = 17\newline7a+45=17-7a + 45 = 17\newlineSubtract 4545 from both sides: 7a=28-7a = -28\newlineDivide by 7-7: a=4a = 4
  4. Substitute back for 'u': Step 44: Substitute the value of 'a' back into the expression for 'u' to find 'u'.\newlineu=92(4)u = 9 - 2(4)\newlineu=98u = 9 - 8\newlineu=1u = 1