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((3)/(x))^(2)×((3)/(x))^(-1)

(3x)2×(3x)1 \left(\frac{3}{x}\right)^{2} \times\left(\frac{3}{x}\right)^{-1}

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Q. (3x)2×(3x)1 \left(\frac{3}{x}\right)^{2} \times\left(\frac{3}{x}\right)^{-1}
  1. Identify Bases and Exponents: Identify the bases and exponents in the expression.\newline((3)/(x))2((3)/(x))^2 has a base of (3/x)(3/x) and an exponent of 22.\newline((3)/(x))(1)((3)/(x))^(-1) has the same base (3/x)(3/x) and an exponent of 1-1.
  2. Combine Terms Using Property: Use the property of exponents that states (am)×(an)=a(m+n)(a^m)\times(a^n) = a^{(m+n)} to combine the terms.\newline(3x)2×(3x)1=(3x)2+(1)\left(\frac{3}{x}\right)^2 \times \left(\frac{3}{x}\right)^{-1} = \left(\frac{3}{x}\right)^{2 + (-1)}
  3. Add Exponents: Add the exponents.\newline2+(1)=12 + (-1) = 1\newlineSo, (3x)2+(1)=(3x)1\left(\frac{3}{x}\right)^{2 + (-1)} = \left(\frac{3}{x}\right)^1
  4. Simplify Expression: Simplify the expression. (3x)1=3x\left(\frac{3}{x}\right)^1 = \frac{3}{x}

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