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(3) Determine the value of 
x so that the square and the rectangle shown have equal perimeters

(33) Determine the value of x x so that the square and the rectangle shown have equal perimeters

Full solution

Q. (33) Determine the value of x x so that the square and the rectangle shown have equal perimeters
  1. Calculate Square Perimeter: Square side length is given as 55 cm, so its perimeter Psquare=4×side=4×5=20P_{\text{square}} = 4 \times \text{side} = 4 \times 5 = 20 cm.
  2. Calculate Rectangle Perimeter: Rectangle lengths are given as xx cm and (x+2)(x + 2) cm, so its perimeter Prectangle=2×(x+x+2)=2×(2x+2)P_{\text{rectangle}} = 2 \times (x + x + 2) = 2 \times (2x + 2).
  3. Set Perimeters Equal: Set the perimeters equal to each other: Psquare=PrectangleP_{\text{square}} = P_{\text{rectangle}}, so 20=2×(2x+2)20 = 2 \times (2x + 2).
  4. Solve for x: Solve for x: 20=4x+420 = 4x + 4.
  5. Subtract 44: Subtract 44 from both sides: 204=4x20 - 4 = 4x, so 16=4x16 = 4x.
  6. Divide by 44: Divide both sides by 44: 16/4=x16 / 4 = x, so x=4x = 4.

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