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$(3^{2}+9)\times([1+9]\times2)=$

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Powers with negative bases

Full solution

Q.

(3^{2}+9)\times([1+9]\times2)=

Calculate $3^2$ : Calculate the value of $3^2$ . $\newline$ $3^2 = 3 \times 3 = 9$
Add $9$ : Add $9$ to the result from Step $1$ . $\newline$ $9$ (from $3^2$ ) + $9$ = $18$
Calculate $[1+9]$ : Calculate the value inside the brackets $[1+9]$ . $\newline$ $1 + 9 = 10$
Multiply by $2$ : Multiply the result from Step $3$ by $2$ . $\newline$ $10 \times 2 = 20$
Multiply Step $2$ and Step $4$ : Multiply the results from Step $2$ and Step $4$ . $18 \times 20 = 360$

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