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(3^(2)+9)×([1+9]×2)

$\left(3^{2}+9\right) \times([1+9] \times 2)$

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Powers with negative bases

Full solution

Q.

\left(3^{2}+9\right) \times([1+9] \times 2)

Calculate $3^2$ : Calculate $3^2$ . $\newline$ $3^2 = 3 \times 3 = 9$
Add $9$ : Add $9$ to the result of $3^2$ . $\newline$ $9 + 9 = 18$
Calculate sum in brackets: Calculate the sum inside the brackets $[1+9]$ . $\newline$ $1 + 9 = 10$
Multiply result by $2$ : Multiply the result inside the brackets by $2$ . $\newline$ $10 \times 2 = 20$
Multiply two results: Multiply the two results together: $18$ from the first part and $20$ from the second part. $\newline$ $18 \times 20 = 360$

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