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{:[3(1)/(2)+4(1)/(4)=>+4=7-],[2(2)/(7)+3(1)/(2)=>+3=5-],[4(1)/(8)+6(3)/(4)=>c+c=10-]:}
30
Undervanding mixed numbers

$\begin{array}{l} 3 \frac{1}{2}+4 \frac{1}{4} \Rightarrow+4=7- \\ 2 \frac{2}{7}+3 \frac{1}{2} \Rightarrow+3=5- \\ 4 \frac{1}{8}+6 \frac{3}{4} \Rightarrow c+c=10- \end{array}$ $\newline$ $30$ $\newline$ Undervanding mixed numbers

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Choose two-step equations: word problems

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Q.

\begin{array}{l} 3 \frac{1}{2}+4 \frac{1}{4} \Rightarrow+4=7- \\ 2 \frac{2}{7}+3 \frac{1}{2} \Rightarrow+3=5- \\ 4 \frac{1}{8}+6 \frac{3}{4} \Rightarrow c+c=10- \end{array}

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30

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Undervanding mixed numbers

Convert to Improper Fractions: Solve the first mixed number problem. $\newline$ The first problem is $3\frac{1}{2} + 4\frac{1}{4} \Rightarrow +4 = 7$ . $\newline$ First, convert the mixed numbers to improper fractions. $\newline$ $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ . $\newline$ $4\frac{1}{4} = \frac{(4\times4 + 1)}{4} = \frac{17}{4}$ . $\newline$ Now, add the improper fractions. $\newline$ To add fractions, they must have a common denominator. The least common denominator (LCD) for $2$ and $4$ is $4$ . $\newline$ Convert $\frac{7}{2}$ to a fraction with a denominator of $4$ : $\frac{(7\times2)}{(2\times2)} = \frac{14}{4}$ . $\newline$ Now add $\frac{14}{4}$ and $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $0$ : $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $1$ . $\newline$ Convert $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $2$ back to a mixed number: $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $3$ . $\newline$ The equation is now $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $4$ . $\newline$ Add $4$ to $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $6$ : $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $7$ . $\newline$ The equation is incorrect because $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $8$ does not equal $3\frac{1}{2} = \frac{(3\times2 + 1)}{2} = \frac{7}{2}$ $9$ .

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