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Let’s check out your problem:

(2x-(7-5x))/(9x-(3+4x))=(7)/(6)

Find xx \newline2x−(7−5x)9x−(3+4x)=76 \frac{2 x-(7-5 x)}{9 x-(3+4 x)}=\frac{7}{6}

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Full solution

Q. Find xx \newline2x−(7−5x)9x−(3+4x)=76 \frac{2 x-(7-5 x)}{9 x-(3+4 x)}=\frac{7}{6}
  1. Simplify Numerator and Denominator: Simplify the numerator and the denominator.\newlineNumerator: 2x−(7−5x)=2x−7+5x=7x−72x - (7 - 5x) = 2x - 7 + 5x = 7x - 7\newlineDenominator: 9x−(3+4x)=9x−3−4x=5x−39x - (3 + 4x) = 9x - 3 - 4x = 5x - 3\newlineEquation becomes: (7x−7)/(5x−3)=7/6(7x - 7) / (5x - 3) = 7 / 6
  2. Cross-Multiply to Eliminate Fractions: Cross-multiply to eliminate the fractions.\newline(7x−7)×6=7×(5x−3)(7x - 7) \times 6 = 7 \times (5x - 3)\newline42x−42=35x−2142x - 42 = 35x - 21
  3. Solve for x: Solve for x.\newline42x−35x=−21+4242x - 35x = -21 + 42\newline7x=217x = 21\newlinex=217x = \frac{21}{7}\newlinex=3x = 3

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