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{:[-2x < 10],[x > (10)/(-2)]:}

(3p-7)/(2) <= 0

$\begin{aligned} -2 x & <10 \\ x & >\frac{10}{-2} \end{aligned}$ $\newline$ $321$ . $\frac{3 p-7}{2} \leq 0$

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Solve advanced linear inequalities

Full solution

Q.

\begin{aligned} -2 x & <10 \\ x & >\frac{10}{-2} \end{aligned}

\newline

321

.

\frac{3 p-7}{2} \leq 0

Isolate variable $p$ : First, let's isolate the variable $p$ by multiplying both sides by $2$ to get rid of the denominator. $\newline$ $\frac{3p - 7}{2} \times 2 \leq 0 \times 2$ $\newline$ $3p - 7 \leq 0$
Add $7$ to both sides: Now, we add $7$ to both sides to further isolate $p$ . $3p - 7 + 7 \leq 0 + 7$ $3p \leq 7$
Divide by $3$ to solve: Finally, we divide both sides by $3$ to solve for $p$ . $\frac{3p}{3} \leq \frac{7}{3}$ $p \leq \frac{7}{3}$

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