(2x-1)(x-5)(x+2)=0 What is a positive root of the given equation?

Identify roots of equation: Identify the roots of the equation by setting each factor equal to zero. (2x-1)=0, (x-5)=0, and (x+2)=0Solve first equation: Solve the first equation (2x-1)=0 for x. 2x-1=0 2x=1 x=1/2Solve second equation: Solve the second equation (x-5)=0 for x. x-5=0 x=5Solve third equation: Solve the third equation (x+2)=0 for x. x+2=0 x=-2Identify positive roots: Identify the positive roots from the solutions found. The positive roots are x=1/2 and x=5.

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(2x-1)(x-5)(x+2)=0
What is a positive root of the given equation?

$(2 x-1)(x-5)(x+2)=0$ $\newline$ What is a positive root of the given equation?

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Algebra 1

Solve linear equations: mixed review

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(2 x-1)(x-5)(x+2)=0

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What is a positive root of the given equation?

Identify roots of equation: Identify the roots of the equation by setting each factor equal to zero. $\newline$ $(2x-1)=0$ , $(x-5)=0$ , and $(x+2)=0$
Solve first equation: Solve the first equation $(2x-1)=0$ for $x$ . $2x-1=0$ $2x=1$ $x=\frac{1}{2}$
Solve second equation: Solve the second equation $(x-5)=0$ for $x$ . $x-5=0$ $x=5$
Solve third equation: Solve the third equation $(x+2)=0$ for $x$ . $x+2=0$ $x=-2$
Identify positive roots: Identify the positive roots from the solutions found. $\newline$ The positive roots are $x=\frac{1}{2}$ and $x=5$ .