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(2x1)(4x+3)(2x-1)(4x+3)

Full solution

Q. (2x1)(4x+3)(2x-1)(4x+3)
  1. Distribute first term: First, distribute the first term of the first binomial, 2x2x, to both terms of the second binomial, (4x+3)(4x + 3). \newline2x(4x)+2x(3)=8x2+6x2x(4x) + 2x(3) = 8x^2 + 6x
  2. Distribute second term: Next, distribute the second term of the first binomial, 1-1, to both terms of the second binomial, (4x+3)(4x + 3).1(4x)+1(3)=4x3-1(4x) + -1(3) = -4x - 3
  3. Add results: Now, add the results of the distributions together to get the final product. 8x2+6x4x38x^2 + 6x - 4x - 3
  4. Combine like terms: Combine like terms, 6x6x and 4x-4x, to simplify the expression.\newline8x2+(6x4x)3=8x2+2x38x^2 + (6x - 4x) - 3 = 8x^2 + 2x - 3

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