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Let’s check out your problem:

(2n-1))/(3)=1+(3n-6)/(4)

2n−1)3=1+3n−64 \frac{2 n-1)}{3}=1+\frac{3 n-6}{4}

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Full solution

Q. 2n−1)3=1+3n−64 \frac{2 n-1)}{3}=1+\frac{3 n-6}{4}
  1. Distribute 1212: Now, distribute 1212 to both parts of the equation.\newline12×2n−13=12×1+12×3n−6412 \times \frac{2n - 1}{3} = 12 \times 1 + 12 \times \frac{3n - 6}{4}
  2. Simplify both sides: Simplify both sides.\newline4×(2n−1)=12+3×(3n−6)4 \times (2n - 1) = 12 + 3 \times (3n - 6)\newline8n−4=12+9n−188n - 4 = 12 + 9n - 18
  3. Combine like terms: Now, let's combine like terms.\newline8n−9n=12−18+48n - 9n = 12 - 18 + 4\newline−1n=−2-1n = -2
  4. Divide by −1-1: Finally, divide both sides by −1-1 to solve for nn.n=−2−1n = \frac{-2}{-1}
  5. Final value of n: So, the value of n is 22.

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