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(2ax^(2)+ax)/(a^(2)x^(3)-x)*(ax+1)/(2x+1)= ?

3737. 2ax2+axa2x3xax+12x+1= \frac{2 a x^{2}+a x}{a^{2} x^{3}-x} \cdot \frac{a x+1}{2 x+1}= ?

Full solution

Q. 3737. 2ax2+axa2x3xax+12x+1= \frac{2 a x^{2}+a x}{a^{2} x^{3}-x} \cdot \frac{a x+1}{2 x+1}= ?
  1. Factor out axax: Factor out axax from the numerator of the first fraction and xx from the denominator.ax(2x+1)x(a2x21)ax+12x+1\frac{ax(2x+1)}{x(a^2x^2-1)}\cdot\frac{ax+1}{2x+1}
  2. Factor difference of squares: Notice that a2x21a^2x^2-1 is a difference of squares and can be factored as ax+1ax+1ax1ax-1. rac{ax(2x+1)}{x(ax+1)(ax-1)} rac{ax+1}{2x+1}
  3. Cancel out terms: Cancel out the (2x+1)(2x+1) terms in the numerator of the first fraction and the denominator of the second fraction.axx(ax+1)(ax1)×(ax+1)\frac{ax}{x(ax+1)(ax-1)}\times(ax+1)
  4. Cancel out terms: Cancel out the (ax+1)(ax+1) terms in the denominator of the first fraction and the numerator of the second fraction.axx(ax1)\frac{ax}{x(ax-1)}
  5. Cancel out terms: Cancel out the xx terms in the numerator and the denominator.aax1\frac{a}{ax-1}
  6. Final simplification: Realize that we can't simplify further since there's no common factor left.

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