Q. 327=35xWatch on9=Youtulube(a) If log5x=9, then x=□(b) If log7x=4, then x=□Submit Question
Divide by 3:(27)/(3)=(5x)/(3)Simplify both sides by dividing by 3.
Multiply to isolate 5x:327=35x9=35xMultiply both sides by 3 to isolate 5x.
Divide to solve for x:9×3=5x27=5xDivide both sides by 5 to solve for x.
Calculate 59:527=xx=5.4
Calculate 74: (a) If log5x=9, then x=59Calculate 5 raised to the power of 9.
Calculate 74: (a) If log5x=9, then x=59Calculate 5 raised to the power of 9. x=59x=1953125
Calculate 74: (a) If log5x=9, then x=59Calculate 5 raised to the power of 9. x=59x=1953125(b) If log7x=4, then x=74Calculate 7 raised to the power of log5x=90.
Calculate 74: (a) If log5x=9, then x=59Calculate 5 raised to the power of 9. x=59x=1953125 (b) If log7x=4, then x=74Calculate 7 raised to the power of log5x=90. log5x=91log5x=92
More problems from Quotient property of logarithms