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(21 n-28n^(2))/(3)÷(12 n-9)/(4)

21n−28n23÷12n−94 \frac{21 n-28 n^{2}}{3} \div \frac{12 n-9}{4}

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Full solution

Q. 21n−28n23÷12n−94 \frac{21 n-28 n^{2}}{3} \div \frac{12 n-9}{4}
  1. Simplify Division: First, let's simplify the division by multiplying by the reciprocal of the second fraction.\newline(21n−28n2)/3×4/(12n−9)(21n - 28n^2) / 3 \times 4 / (12n - 9)
  2. Multiply Numerators and Denominators: Now, simplify the expression by multiplying the numerators and denominators. \newline(21n−28n2)×4/(3×(12n−9))(21n - 28n^2) \times 4 / (3 \times (12n - 9))
  3. Distribute Numbers: Distribute the 44 into the numerator and the 33 into the denominator.\newline84n−112n236n−27\frac{84n - 112n^2}{36n - 27}
  4. Factor Out Common Terms: Now, we can try to factor out common terms, but there's no common factor between the terms in the numerator and the denominator.\newlineSo, the expression is already simplified.

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