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egin{20-20x+1212y=2424} and egin{5-5x+22y= rac{66}{}} consider the system of equations. how many egin{(x,y)} solutions does this system have?

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Q. egin{20-20x+1212y=2424} and egin{5-5x+22y= rac{66}{}} consider the system of equations. how many egin{(x,y)} solutions does this system have?
  1. Analyze Equations: Analyze the system of equations to determine if they are multiples of each other.\newlineThe system of equations is:\newline20x+12y=24-20x + 12y = 24\newline5x+2y=6-5x + 2y = 6\newlineWe can simplify the first equation by dividing all terms by 44:\newline20x/4+12y/4=24/4-20x/4 + 12y/4 = 24/4\newline5x+3y=6-5x + 3y = 6\newlineNow, compare the simplified first equation with the second equation:\newline5x+3y=6-5x + 3y = 6\newline5x+2y=6-5x + 2y = 6\newlineWe can see that the coefficients of xx are the same in both equations, but the coefficients of yy and the constants are different.
  2. Simplify First Equation: Since the coefficients of xx are the same but the coefficients of yy and the constants are different, we can conclude that the lines represented by these equations are parallel.\newlineParallel lines never intersect, which means there are no points (x,y)(x, y) that satisfy both equations simultaneously.

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