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(-2+x)/(3+x)=6

2+x3+x=6 \frac{-2+x}{3+x}=6

Full solution

Q. 2+x3+x=6 \frac{-2+x}{3+x}=6
  1. Multiply to eliminate denominator: Isolate xx by multiplying both sides by (3+x)(3+x) to eliminate the denominator; (2+x)=6(3+x)(-2+x) = 6(3+x).
  2. Distribute on right side: Distribute 66 on the right side; (2+x)=18+6x(-2+x) = 18 + 6x.
  3. Rearrange terms: Move all xx terms to one side and constant terms to the other; x6x=18+2x - 6x = 18 + 2.

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