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{:[(2)sqrt(sqrt(2b-1)+sqrt5=2)],[sqrt(2b-1)=2sqrtb]:}

(2)2b1+5=22b1=2b \begin{array}{l}(2) \sqrt{\sqrt{2 b-1}+\sqrt{5}=2} \\ \sqrt{2 b-1}=2 \sqrt{b}\end{array}

Full solution

Q. (2)2b1+5=22b1=2b \begin{array}{l}(2) \sqrt{\sqrt{2 b-1}+\sqrt{5}=2} \\ \sqrt{2 b-1}=2 \sqrt{b}\end{array}
  1. Identify number type: Identify the type of number 5.1195.119 is.\newline5.1195.119 is a number with a finite number of decimal places.
  2. Determine termination: Determine if 5.1195.119 is a terminating or non-terminating decimal. Since 5.1195.119 stops after three decimal places, it is a terminating decimal.
  3. Recall irrational definition: Recall the definition of an irrational number. An irrational number cannot be expressed as a fraction of two integers and has non-terminating, non-repeating decimals.
  4. Compare to definition: Compare 5.1195.119 to the definition of an irrational number.\newline5.1195.119 is a terminating decimal, so it can be expressed as a fraction (5119/1000)(5119/1000).
  5. Conclude rationality: Conclude whether 5.1195.119 is irrational or not.\newline5.1195.119 is not an irrational number because it is a terminating decimal.

More problems from Checkpoint: Rational and irrational numbers