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−
2
3
×
[
3
5
+
(
−
5
6
)
]
=
?
\frac{-2}{3} \times\left[\frac{3}{5}+\left(\frac{-5}{6}\right)\right]=?
3
−
2
×
[
5
3
+
(
6
−
5
)
]
=
?
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Home
Math Problems
Algebra 2
Evaluate rational exponents
Full solution
Q.
−
2
3
×
[
3
5
+
(
−
5
6
)
]
=
?
\frac{-2}{3} \times\left[\frac{3}{5}+\left(\frac{-5}{6}\right)\right]=?
3
−
2
×
[
5
3
+
(
6
−
5
)
]
=
?
Convert to common denominator:
(\frac{3}{5}) + (\frac{-5}{6}) = (\frac{3\times6}{5\times6}) + (\frac{-5\times5}{6\times5})\(\newline= (\frac{18}{30}) + (\frac{-25}{30})
\newline
= (\frac{-7}{30})\)
Multiply by
(
−
2
)
/
(
3
)
(-2)/(3)
(
−
2
)
/
(
3
)
:
Now, multiply the result by
(
−
2
)
/
(
3
)
(-2)/(3)
(
−
2
)
/
(
3
)
.
−
2
3
×
−
7
30
=
2
×
7
3
×
30
\frac{-2}{3} \times \frac{-7}{30} = \frac{2\times7}{3\times30}
3
−
2
×
30
−
7
=
3
×
30
2
×
7
=
14
90
= \frac{14}{90}
=
90
14
Simplify the fraction:
Simplify the fraction.
(
14
)
/
(
90
)
=
(
7
)
/
(
45
)
(14)/(90) = (7)/(45)
(
14
)
/
(
90
)
=
(
7
)
/
(
45
)
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