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$- \frac{2}{3}(12r - 6) =$

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Powers with decimal bases

Full solution

Q.

- \frac{2}{3}(12r - 6) =

Distribute $-\frac{2}{3}$ : First, distribute $-\frac{2}{3}$ to both terms inside the parentheses. $\newline$ $-\frac{2}{3} \times 12r$ gives $-8r$ , and $-\frac{2}{3} \times -6$ gives $+4$ . $\newline$ So, $-\frac{2}{3}(12r - 6)$ becomes $-8r + 4$ .
Check distribution: Check the distribution for any mistakes. $\newline$ $-\frac{2}{3} \times 12r$ is indeed $-8r$ , and $-\frac{2}{3} \times -6$ is indeed $+4$ . $\newline$ No errors found.

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