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[[2,-3,1,-1],[-4,9,0,14],[0,0,1,3]]
-. How to solve this!

[2311490140013] \left[\begin{array}{rrr|r} 2 & -3 & 1 & -1 \\ -4 & 9 & 0 & 14 \\ 0 & 0 & 1 & 3 \end{array}\right] \newline-. How to solve this!

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Q. [2311490140013] \left[\begin{array}{rrr|r} 2 & -3 & 1 & -1 \\ -4 & 9 & 0 & 14 \\ 0 & 0 & 1 & 3 \end{array}\right] \newline-. How to solve this!
  1. Write Matrix: Write down the matrix to find its determinant.\newlineMatrix: [231 490 001]\begin{bmatrix} 2 & -3 & 1 \ -4 & 9 & 0 \ 0 & 0 & 1 \end{bmatrix}
  2. Use Formula: Use the formula for the determinant of a 3×33 \times 3 matrix.det(A)=a(eifh)b(difg)+c(dheg)\text{det}(A) = a(ei − fh) − b(di − fg) + c(dh − eg)
  3. Substitute Values: Substitute the values from the matrix into the formula.\newlinedet(A)=2(9×10×0)(3)(4×10×1)+1(4×09×0)\text{det}(A) = 2(9\times 1 - 0\times 0) - (-3)(-4\times 1 - 0\times 1) + 1(-4\times 0 - 9\times 0)
  4. Perform Calculations: Perform the calculations.\newlinedet(A)=2(9)(3)(4)+1(0)\text{det}(A) = 2(9) - (-3)(-4) + 1(0)\newlinedet(A)=1812+0\text{det}(A) = 18 - 12 + 0
  5. Add Final Determinant: Add up the results to get the final determinant.\newlinedet(A)=1812\text{det}(A) = 18 - 12\newlinedet(A)=6\text{det}(A) = 6

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