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(15) 
0=12 m+60

(10)

(1515) 0=12m+60 0=12 m+60 \newline(10) (10)

Full solution

Q. (1515) 0=12m+60 0=12 m+60 \newline(10) (10)
  1. Subtract 6060 from both sides: First, let's subtract 6060 from both sides to isolate the term with mm.\newline060=12m+60600 - 60 = 12m + 60 - 60\newline60=12m-60 = 12m
  2. Divide both sides by 1212: Now, we divide both sides by 1212 to solve for mm.6012=12m12-\frac{60}{12} = \frac{12m}{12}5=m-5 = m

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