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(12-9i)+(32-6i)=
Express your answer in the form 
(a+bi).

(129i)+(326i)= (12-9 i)+(32-6 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (129i)+(326i)= (12-9 i)+(32-6 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Identify parts of complex numbers: Identify the real and imaginary parts of each complex number.\newlineThe real part of the first complex number (129i)(12-9i) is 1212, and the imaginary part is 9i-9i.\newlineThe real part of the second complex number (326i)(32-6i) is 3232, and the imaginary part is 6i-6i.
  2. Add real parts: Add the real parts together.\newlineAdd the real parts of the complex numbers: 1212 (from the first complex number) and 3232 (from the second complex number).\newlineCalculation: 12+32=4412 + 32 = 44
  3. Add imaginary parts: Add the imaginary parts together.\newlineAdd the imaginary parts of the complex numbers: 9i-9i (from the first complex number) and 6i-6i (from the second complex number).\newlineCalculation: 9i+6i=15i-9i + -6i = -15i
  4. Combine sums to form complex number: Combine the sums of the real and imaginary parts to form a single complex number.\newlineCombine the sum of the real parts 4444 with the sum of the imaginary parts 15i-15i to form the complex number 4415i44 - 15i.

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