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-10*(13 i-9)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$-10 \cdot(13 i-9)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

-10 \cdot(13 i-9)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Multiply real part by $-10$ : Multiply the real part of the complex number by $-10$ . The real part of the complex number is $-9$ . Multiplying this by $-10$ gives us $90$ .
Multiply imaginary part by $-10$ : Multiply the imaginary part of the complex number by $-10$ . The imaginary part of the complex number is $13i$ . Multiplying this by $-10$ gives us $-130i$ .
Combine results for final complex number: Combine the results from Step $1$ and Step $2$ to form the final complex number. $\newline$ The real part from Step $1$ is $90$ , and the imaginary part from Step $2$ is $-130i$ . Combining these gives us the complex number $90 - 130i$ .

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