\# $10$ $-11$ You are building a sandbox in your backyard. The diagram shows the four vertices of the bottom of the sandbox. Each unit in the coordinate plane represents $1$ foot. Find the perimeter and area of the bottom of the sandbox. $\newline$ $10$ . Perimeter $\newline$ $11$ . Area

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Q. \#

10

-11

You are building a sandbox in your backyard. The diagram shows the four vertices of the bottom of the sandbox. Each unit in the coordinate plane represents

1

foot. Find the perimeter and area of the bottom of the sandbox.

\newline

10

. Perimeter

\newline

11

. Area

Identify Sandbox Sides: First, we need to figure out the lengths of the sides of the sandbox. Since it's a rectangle, opposite sides are equal. Let's find the length of the bottom and the right side.
Calculate Side Lengths: The bottom side goes from $(0,0)$ to $(3,0)$ . So the length is $3 - 0 = 3$ feet.
Calculate Perimeter: The right side goes from $(3,0)$ to $(3,2)$ . So the length is $2 - 0 = 2$ feet.
Calculate Area: Now, let's calculate the perimeter. The perimeter $P$ of a rectangle is $2$ times the length plus $2$ times the width. So, $P = 2 \times \text{length} + 2 \times \text{width}$ .
Calculate Area: Now, let's calculate the perimeter. The perimeter $P$ of a rectangle is $2$ times the length plus $2$ times the width. So, $P = 2 \times \text{length} + 2 \times \text{width}$ .Plug in the values we found. $P = 2 \times 3 + 2 \times 2$ .
Calculate Area: Now, let's calculate the perimeter. The perimeter $P$ of a rectangle is $2$ times the length plus $2$ times the width. So, $P = 2 \times \text{length} + 2 \times \text{width}$ .Plug in the values we found. $P = 2 \times 3 + 2 \times 2$ .Do the math. $P = 6 + 4 = 10$ feet.
Calculate Area: Now, let's calculate the perimeter. The perimeter $P$ of a rectangle is $2$ times the length plus $2$ times the width. So, $P = 2 \times \text{length} + 2 \times \text{width}$ .Plug in the values we found. $P = 2 \times 3 + 2 \times 2$ .Do the math. $P = 6 + 4 = 10$ feet.Now for the area $A$ , which is length times width for a rectangle.
Calculate Area: Now, let's calculate the perimeter. The perimeter $P$ of a rectangle is $2$ times the length plus $2$ times the width. So, $P = 2 \times \text{length} + 2 \times \text{width}$ .Plug in the values we found. $P = 2 \times 3 + 2 \times 2$ .Do the math. $P = 6 + 4 = 10$ feet.Now for the area $A$ , which is length times width for a rectangle.Plug in the values. $A = 3 \times 2$ .
Calculate Area: Now, let's calculate the perimeter. The perimeter $P$ of a rectangle is $2$ times the length plus $2$ times the width. So, $P = 2 \times \text{length} + 2 \times \text{width}$ .Plug in the values we found. $P = 2 \times 3 + 2 \times 2$ .Do the math. $P = 6 + 4 = 10$ feet.Now for the area $A$ , which is length times width for a rectangle.Plug in the values. $A = 3 \times 2$ .Do the math. $A = 6$ square feet.