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(1-x^(2))(1-y^(2))+4xy

(1−x2)(1−y2)+4xy \left(1-x^{2}\right)\left(1-y^{2}\right)+4 x y

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Full solution

Q. (1−x2)(1−y2)+4xy \left(1-x^{2}\right)\left(1-y^{2}\right)+4 x y
  1. Expand First Term: Expand the first term (1−x2)(1−y2)(1-x^{2})(1-y^{2}) using the distributive property (FOIL method).(1−x2)(1−y2)=1(1)−1(y2)−x2(1)+x2(y2)(1-x^{2})(1-y^{2}) = 1(1) - 1(y^{2}) - x^{2}(1) + x^{2}(y^{2})=1−y2−x2+x2y2= 1 - y^{2} - x^{2} + x^{2}y^{2}
  2. Add Second Term: Add the second term 4xy4xy to the expanded expression.\newline1−y2−x2+x2y2+4xy1 - y^2 - x^2 + x^2y^2 + 4xy
  3. Combine Like Terms: Combine like terms if there are any; in this case, there are no like terms to combine.\newlineSo the expression remains 1−y2−x2+x2y2+4xy1 - y^2 - x^2 + x^2y^2 + 4xy

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