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(1) Find the equation of the straight line (-5,3) and (-4,1)

(11) Find the equation of the straight line (−5,3) (-5,3) and (−4,1) (-4,1)

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Full solution

Q. (11) Find the equation of the straight line (−5,3) (-5,3) and (−4,1) (-4,1)
  1. Calculate slope: Calculate the slope mm of the line using the formula m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points.\newlinem=1−3−4+5m = \frac{1 - 3}{-4 + 5}
  2. Simplify calculation: Simplify the calculation of the slope.\newlinem=−2/1m = -2 / 1\newlinem=−2m = -2
  3. Use point-slope form: Use the point-slope form of the equation of a line, y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line.\newlineLet's use the point (−5,3)(-5, 3).\newliney−3=−2(x+5)y - 3 = -2(x + 5)

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