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$1 and 2 are complementarg. If
m/_1=7x+16 and
m/_2=4x-5 then find measure of
/_2.

$\$ 1$ and $2$ are complementarg. If $m \angle 1=7 x+16$ and $m \angle 2=4 x-5$ then find measure of $\angle 2$ .

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Write and solve inverse variation equations

Full solution

Q.

\$ 1

and

2

are complementarg. If

m \angle 1=7 x+16

and

m \angle 2=4 x-5

then find measure of

\angle 2

.

Write Equation: Angles $1$ and $2$ are complementary, so their measures add up to $90$ degrees. $\newline$ Write the equation: $(7x + 16) + (4x - 5) = 90$ .
Combine Like Terms: Combine like terms: $7x + 4x + 16 - 5 = 90$ . This simplifies to: $11x + 11 = 90$ .
Isolate Variable Term: Subtract $11$ from both sides to isolate the variable term: $11x = 79$ .
Solve for x: Divide both sides by $11$ to solve for x: $x = \frac{79}{11}$ . $\newline$ Calculate $x$ : $x = 7.18181818\ldots$ (This looks a bit off, let's double-check the math in the previous step).

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