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(" № "1)/(" Сравнить "80^(13)×10^(28)).

 № 1 Сравнить 8013×1028 \frac{\text { № } 1}{\text { Сравнить } 80^{13} \times 10^{28}} .

Full solution

Q.  № 1 Сравнить 8013×1028 \frac{\text { № } 1}{\text { Сравнить } 80^{13} \times 10^{28}} .
  1. Express as Product: Now, let's express 801380^{13} as (24×5)13(2^4 \times 5)^{13}.
  2. Apply Power Rule: Using the power of a product rule, (ab)n=anbn(a*b)^n = a^n * b^n, we get 24135132^{4*13} * 5^{13}.
  3. Calculate Exponents: So, 24×132^{4\times13} is 2522^{52} and 5135^{13} remains the same. Now we have 252×513.2^{52} \times 5^{13}.
  4. Multiply by 102810^{28}: Next, let's multiply 252×5132^{52} \times 5^{13} by 102810^{28}. Since 1010 is 2×52\times5, we can write 102810^{28} as 228×5282^{28} \times 5^{28}.
  5. Combine Exponents: Now we multiply the exponents with the same base: 252×2282^{52} \times 2^{28} and 513×528.5^{13} \times 5^{28}.
  6. Final Answer: Adding the exponents for the same bases gives us 2(52+28)2^{(52+28)} and 5(13+28)5^{(13+28)}.
  7. Final Answer: Adding the exponents for the same bases gives us 252+282^{52+28} and 513+285^{13+28}.So, 252+282^{52+28} is 2802^{80} and 513+285^{13+28} is 5415^{41}. Now we have 280×5412^{80} \times 5^{41}.
  8. Final Answer: Adding the exponents for the same bases gives us 252+282^{52+28} and 513+285^{13+28}.So, 252+282^{52+28} is 2802^{80} and 513+285^{13+28} is 5415^{41}. Now we have 280×5412^{80} \times 5^{41}.Finally, we combine the exponents with the same base to get the final answer: 280×5412^{80} \times 5^{41}.

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