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1(2x8)2=144-1(2x-8)^2=-144

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Q. 1(2x8)2=144-1(2x-8)^2=-144
  1. Take Square Root: Now, take the square root of both sides to solve for 2x82x-8.(2x8)2=±144\sqrt{(2x-8)^2} = \pm\sqrt{144}2x8=±122x - 8 = \pm12
  2. Solve for x (Positive Root): Next, we'll solve for x by adding 88 to both sides of the equation.\newlineFor the positive root:\newline2x8+8=12+82x - 8 + 8 = 12 + 8\newline2x=202x = 20
  3. Isolate x (Positive Root): Divide both sides by 22 to isolate xx.2x2=202\frac{2x}{2} = \frac{20}{2}x=10x = 10
  4. Solve for x (Negative Root): Now, let's solve for the negative root.\newline2x8+8=12+82x - 8 + 8 = -12 + 8\newline2x=42x = -4
  5. Isolate x (Negative Root): Divide both sides by 22 to isolate x.\newline2x2=42\frac{2x}{2} = \frac{-4}{2}\newlinex=2x = -2

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