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(((1)/(2))/(2+2))/((2+2+2)/((2+2+2)/(2+2)))

122+22+2+22+2+22+2 \frac{\frac{\frac{1}{2}}{2+2}}{\frac{2+2+2}{\frac{2+2+2}{2+2}}}

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Full solution

Q. 122+22+2+22+2+22+2 \frac{\frac{\frac{1}{2}}{2+2}}{\frac{2+2+2}{\frac{2+2+2}{2+2}}}
  1. Simplify Numerator: Simplify the numerator and denominator separately.\newlineNumerator: (12)/(2+2)=12/4=18\left(\frac{1}{2}\right)/(2+2) = \frac{1}{2}/4 = \frac{1}{8}\newlineDenominator: (2+2+2(2+2+2)/(2+2))=6(6/4)=6×(46)=4\left(\frac{2+2+2}{\left(2+2+2\right)/(2+2)}\right) = \frac{6}{\left(6/4\right)} = 6 \times \left(\frac{4}{6}\right) = 4
  2. Simplify Denominator: Divide the simplified numerator by the simplified denominator.\newline(18)/4=18∗14=132(\frac{1}{8}) / 4 = \frac{1}{8} * \frac{1}{4} = \frac{1}{32}

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